Highway bars mounted on my 2006 K9

Black Rider

Active Member
Thats the clearest explanation i have ever read. :roll::roll::roll::roll:
Yeah? Well it got me scared as hell. Must have read it 10 times before the suspect signs came on....
Made my day though. People at work were wondering why I had the long face.
 

tommy666

Well-Known Member
I called Rivco. Are they the 1-1/2" universals? They said they stick out 13". Was it mandatory for the 3" extensions? Just curious? I'm still gonna buy'em.
 

stryfox

Active Member
If you heat the stickers with a hair dryer to warm them you should be able to get them off in one piece.
I put mine on a piece of wax paper and put it away with my title.
You guys are too funny. :)
 

Black Rider

Active Member
I called Rivco. Are they the 1-1/2" universals? They said they stick out 13". Was it mandatory for the 3" extensions? Just curious? I'm still gonna buy'em.
I can't remember off the top of my head the size. Here is my invoice number if u give them they can look up my order: 40294

As for the extensions they help if u get an updated air filter or like me long legged. Let me know if u need more. Stephenie helped me. :flag:
 

LukeDM

Active Member
OK, here it goes...


If the speed of the object (with the sticker) increases but the circumference is doubled (frame tube), the angular velocity (degrees or radians of the angle covered by the radius connecting the object to the centre or thickness of sticker) will become double its earlier value. Its period for each rotation will become triple its earlier value and will eventually slow the foward velocity of the forgoing molecules.

On the other hand, if its angular velocity has to remain unchanged (constant), it has to move at double the velocity in the tangential direction. Its period of rotation will remain same .
It can mostly be explained by this formula.

Sinθ*Cosθ/Radius(1.35in) Then you use the eleventh trigonometric function (Sin*sin*cos*cos=1) to get yourself to this. 1/SinθCosθ*R
The reciprocal of Sin is Csc. The reciprocal of Cos is Sec. So now what you have is CscθSecθ*R. You take your common Sin diagram

And your common Cos diagram

The points of 1.35 on Sin is about .85 is nearly -.78
Multiply the two and you get -0.663.
-0.663 is now your velocity.
Take your Velocity (V). Now if you apply it to your special 30,60,90 triangle

You can clearly see that the negative number applied to any of the angles (Using the second variation of the 16th trigonometric function, Cos*Cos-1=Cos2θ) will make your side lengths (1,2, and the square root of 3) much less than they originally were. The percentage of loss in the triangle (About 18.73%) is = loss of horsepower.
 

LukeDM

Active Member
I'm really just messing with you, blackrider. :lol: Glad you know how to take a little bit of joking. :2thumbs:
 

tommy666

Well-Known Member
Mine arrive tomorrow. A big Thank You to Black Biker! I was going to get some custom made! Thank You for the info! Leg's up high and rid'n it like it was Stolen!!!!!!!!!!!
 

Black Rider

Active Member
Ok u jokers. Used a heat gun today and removed the stickers. Put them on the fender under the seat. The highway bars are awesome. Finished the wire plus install last night and ride all day. I highly recommend the highway bars. Plus they do not look bad on the bike. I will post pics after I wash it tomorrow.
 
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