OK, here it goes...
If the speed of the object (with the sticker) increases but the circumference is doubled (frame tube), the angular velocity (degrees or radians of the angle covered by the radius connecting the object to the centre or thickness of sticker) will become double its earlier value. Its period for each rotation will become triple its earlier value and will eventually slow the foward velocity of the forgoing molecules.
On the other hand, if its angular velocity has to remain unchanged (constant), it has to move at double the velocity in the tangential direction. Its period of rotation will remain same .
It can mostly be explained by this formula.
Sinθ*Cosθ/Radius(1.35in) Then you use the eleventh trigonometric function (Sin*sin*cos*cos=1) to get yourself to this. 1/SinθCosθ*R
The reciprocal of Sin is Csc. The reciprocal of Cos is Sec. So now what you have is CscθSecθ*R. You take your common Sin diagram
And your common Cos diagram
The points of 1.35 on Sin is about .85 is nearly -.78
Multiply the two and you get -0.663.
-0.663 is now your velocity.
Take your Velocity (V). Now if you apply it to your special 30,60,90 triangle
You can clearly see that the negative number applied to any of the angles (Using the second variation of the 16th trigonometric function, Cos*Cos-1=Cos2θ) will make your side lengths (1,2, and the square root of 3) much less than they originally were. The percentage of loss in the triangle (About 18.73%) is = loss of horsepower.