Jumping bike with a car

Energy One

BIGDOG88

Member
I have read a lot of post saying if you jump a bike off with a car do not have car running. Why can’t the car be running. What will happen if you jump bike while the vehicle is running? What damage will occur? Thank you.
 

SKOGDOG

One of the old ones.
A car with the engine running makes a lot more current because the alternator is operating, which can damage the bikes electronics.
With the ignition off it isolates the car battery at its basic 12V. Disconnect immediately when the bike starts.
 

BIGDOG88

Member
A car with the engine running makes a lot more current because the alternator is operating, which can damage the bikes electronics.
With the ignition off it isolates the car battery at its basic 12V. Disconnect immediately when the bike starts.
Thank you.
 

Sven

Well-Known Member
Car battery alone is like a silo holding cobs, same volts are the cobs.
A bike battery is like a bucket, still holds 12v cobs, but holds so much storage.

Car's amp output is 65a times 12v = 5 watts.
Bike's amp is 32a X 12v = 2 watts.

WATT happens if I stick an elephants foot up a mouse's ass-ass the mouse is 'running' from it? Answer!
 

Nukeranger

Nukeranger
And I thought it was because the voltage is much higher with the car running which creates more amps to the bike with a higher voltage.
 

Mr. Wright

Knows some things
Supporting Member
Same thing in reverse, when using one of those little jump boxes. Soon as it starts pull the jump box off, it might explode. It happened to someone on here. And I had a guy I was helping on the phone, who was jumping his bike with the car running, and left the cables on, and his EHC exploded.
 

41bigdawg

Let the Big Dawg eat !
Sven wins the prize for best explanation :) It crazy and took a couple of years but sometimes I actually understand what he is talking about and he says "Nobody Listens to Turtle" NLTT
 

Clay9

Member
Mr Wright, I have a NOCO jump box and NOCO pigtails on my bikes for jump starting. How did one blow up????
 

Mr. Wright

Knows some things
Supporting Member
I just remember someone telling about the jump box popping, from leaving it on after the bike started.
 

Clay9

Member
Oh, ok. I never leave it on very long, but it takes a few seconds to remove once the bike has started.
 

Sven

Well-Known Member
And I thought it was because the voltage is much higher with the car running which creates more amps to the bike with a higher voltage.
Both car and bike have the same 14.+ charge rate. Ohm's wheel has watt designated as P for power. I'll assume a Power plant is why that P name is for selling the watts.

I'm not sure if this next analogy is going to work, but, forget the net, I'm on my own. I'm wondering if a 3w taillight bulb, and a martial arts throwing star could make this work?
The black box has a limit rated at 2w say. It too acts like a resistor and can take the heat up to an imaginary 3w. Where the star comes in, is the star has 4 sides as it travels; think ohm's wheel. The amp is the flow up the wire to the VR. Would you agree E flows outside and inside the wire? Where someone touches a high tension wire and the E found the fastest path out of the line? So imagine a slap in the face is 3w, a punch in the face is 'Double the Power' at a 5w blow at a 3w bulb. That filament is rated for 3w for that brightness, the filament length, etc.

Where the star comes in is; show me how you can separate E and those 4 components? That star does not flow with 3 components missing, and when you have a low battery, the bike/car starts, the lights go dim, but a rev brightens the headlight and taillight up, not a low charged battery. So didn't the amp of 2+ brighten that bulb? Wasn't that 5w watt with all the spokes attached; cook that box into a brick?

So with all the laws, I might have picked the wrong law [Faraday's laws]. So theory wise, E is also that letter for EVEN, or a measured balance of all that is E. So like the resistance of say the box was built to flux even with 32a, you took the 5a flux and on the one loop back is the wave, the hardware was maxed out to flux 3a, but on the backwash thru the flow of the diode, you shot 3a + 5a = 8 / 2 = 4 amp'd the 3w bulb to a balance of 4a. U-turn blew the box buy 1 ampay the cashier on your way out.

Disclaimer: It's halfactheory, halfrom out my ass with lashes; of said balancing act is E.
 
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